Física·Castilla y León·2010·Extraordinaria·Variante 2Datos generales del exameng0=9,8 m/s2g_0 = 9{,}8\,\text{m/s}^2g0=9,8m/s2G=6,67⋅10−11 N⋅m2/kg2G = 6{,}67 \cdot 10^{-11}\,\text{N}\cdot\text{m}^2/\text{kg}^2G=6,67⋅10−11N⋅m2/kg2RT=6,37⋅106 mR_T = 6{,}37 \cdot 10^6\,\text{m}RT=6,37⋅106mMT=5,98⋅1024 kgM_T = 5{,}98 \cdot 10^{24}\,\text{kg}MT=5,98⋅1024kgK0=1/(4πε0)=9⋅109 N⋅m2/C2K_0 = 1/(4\pi\varepsilon_0) = 9 \cdot 10^9\,\text{N}\cdot\text{m}^2/\text{C}^2K0=1/(4πε0)=9⋅109N⋅m2/C2μ0=4π⋅10−7 N/A2\mu_0 = 4\pi \cdot 10^{-7}\,\text{N/A}^2μ0=4π⋅10−7N/A2e=1,60⋅10−19 Ce = 1{,}60 \cdot 10^{-19}\,\text{C}e=1,60⋅10−19Cme=9,11⋅10−31 kgm_e = 9{,}11 \cdot 10^{-31}\,\text{kg}me=9,11⋅10−31kgc0=3⋅108 m/sc_0 = 3 \cdot 10^8\,\text{m/s}c0=3⋅108m/sh=6,63⋅10−34 J⋅sh = 6{,}63 \cdot 10^{-34}\,\text{J}\cdot\text{s}h=6,63⋅10−34J⋅s1 u=1,66⋅10−27 kg1\,\text{u} = 1{,}66 \cdot 10^{-27}\,\text{kg}1u=1,66⋅10−27kg1 eV=1,60⋅10−19 J1\,\text{eV} = 1{,}60 \cdot 10^{-19}\,\text{J}1eV=1,60⋅10−19JEjercicio5Opción B2 puntosUn electrón se acelera, desde el reposo, mediante un potencial eléctrico de 104 V10^4\,\text{V}104V. Calcule:a)1 ptsSu velocidad final.b)1 ptsSu longitud de onda asociada.