31:Tee3,

E^0(\ce{NO3-/NO}) = +0{,}96\,V

2e:["$","li","1",{"className":"min-w-0 max-w-full sm:whitespace-nowrap","children":["$","span",null,{"className":"whitespace-pre-line sm:whitespace-nowrap","children":[["$","span","0",{"className":"whitespace-nowrap","dangerouslySetInnerHTML":{"__html":"$31"}}]]}]}] 32:Ta7f,

E^0(\ce{Au^{3+}/Au}) = +1{,}50\,V

2f:["$","li","2",{"className":"min-w-0 max-w-full sm:whitespace-nowrap","children":["$","span",null,{"className":"whitespace-pre-line sm:whitespace-nowrap","children":[["$","span","0",{"className":"whitespace-nowrap","dangerouslySetInnerHTML":{"__html":"$32"}}]]}]}] 33:T98a,(

\ce{NO3-}

);30:["$","div",null,{"className":"flex flex-col gap-7","children":[["$","$1","0",{"children":[null,["$","div",null,{"className":"grid grid-cols-[minmax(1.25rem,max-content)_1.75rem_minmax(0,1fr)_0rem] gap-x-2 sm:grid-cols-[minmax(2.75rem,max-content)_2rem_minmax(0,1fr)_4rem] sm:gap-x-3","children":[["$","span",null,{"className":"font-heading text-xl font-semibold leading-snug text-primary","children":"a"}],["$","div",null,{"className":"col-span-3 grid grid-cols-subgrid","children":[null,[["$","div",null,{"className":"col-span-2 text-[17px] leading-relaxed","children":[["$","div",null,{"className":"flow-root","children":[["$","span",null,{"className":"whitespace-pre-line","children":[["$","$1","0",{"children":"Deduce razonadamente por qué el "}],["$","span","1",{"className":"whitespace-nowrap","dangerouslySetInnerHTML":{"__html":"

\\ce{Fe(II)}

"}}],["$","$1","2",{"children":" puede ser oxidado en medio ácido a "}],["$","span","3",{"className":"whitespace-nowrap","dangerouslySetInnerHTML":{"__html":"

\\ce{Fe(III)}

"}}],["$","$1","4",{"children":" por el ion nitrato "}],["$","span","5",{"className":"whitespace-nowrap","dangerouslySetInnerHTML":{"__html":"$33"}}],"$L34","$L35","$L36","$L37","$L38","$L39","$L3a"]}],"$L3b"]}],"$L3c"]}],"$L3d"],null]}]]}]]}],"$L3e"]}]